4p^2+0*p+3=103

Solution for 4p^2+0*p+3=103 equation:

4p^2+0p+3=103

We move all terms to the left:

4p^2+0p+3-(103)=0

We add all the numbers together, and all the variables

4p^2+p-100=0

a = 4; b = 1; c = -100;
Δ = b2-4ac
Δ = 12-4·4·(-100)
Δ = 1601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1601}}{2*4}=\frac{-1-\sqrt{1601}}{8}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1601}}{2*4}=\frac{-1+\sqrt{1601}}{8}
$